Use actual hostname instead of example.com in subdirectory/subdomain examples. fixes #12679, props johnbillion.

git-svn-id: http://svn.automattic.com/wordpress/trunk@13811 1a063a9b-81f0-0310-95a4-ce76da25c4cd
This commit is contained in:
nacin 2010-03-25 02:49:23 +00:00
parent c2a6f28bf5
commit d2643077d7
1 changed files with 2 additions and 2 deletions

View File

@ -139,11 +139,11 @@ function network_step1( $errors = false ) {
<table class="form-table">
<tr>
<th><label><input type='radio' name='subdomain_install' value='1'<?php checked( $subdomain_install ); ?> /> Sub-domains</label></th>
<td><?php _e('like <code>site1.example.com</code> and <code>site2.example.com</code>'); ?></td>
<td><?php printf( _x( 'like <code>site1.%1$s</code> and <code>site2.%1$s</code>', 'subdomain examples' ), $hostname ); ?></td>
</tr>
<tr>
<th><label><input type='radio' name='subdomain_install' value='0'<?php checked( ! $subdomain_install ); ?> /> Sub-directories</label></th>
<td><?php _e('like <code>example.com/site1</code> and <code>example.com/site2</code>'); ?></td>
<td><?php printf( _x( 'like <code>%1$s/site1</code> and <code>%1$s/site2</code>', 'subdirectory examples' ), $hostname ); ?></td>
</tr>
</table>